Answer to Question #16797 in Calculus for hsd
f(t) = (t + 1) e^[√(t+2)]
Use logarithmic differentiation in order to determine the relative growth rate at time t = 3 and give your result in percent growth per hour.
f'(t)=(t + 1) e^[√(t+2)](1/(t+1))(1+(t+1)/2√(2+t))
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