# Answer on Calculus Question for akansha

Question #16186

if xy=1 then y^2 +dy/dx is =??

Expert's answer

xy=1

y=1/x

dy/dx=-1/x^2

-1/x^2=-y^2

y^2-dy/dx=y^2-y^2=0

y=1/x

dy/dx=-1/x^2

-1/x^2=-y^2

y^2-dy/dx=y^2-y^2=0

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## Comments

Assignment Expert10.10.2012 07:22You're welcome. We are glad to be helpful.

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akansha10.10.2012 00:52thanx...............

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