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Answer to Question #16186 in Calculus for akansha

Question #16186
if xy=1 then y^2 +dy/dx is =??
Expert's answer
xy=1
y=1/x

dy/dx=-1/x^2

-1/x^2=-y^2

y^2-dy/dx=y^2-y^2=0

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Assignment Expert
10.10.12, 14:22

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akansha
10.10.12, 07:52

thanx...............

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