# Answer to Question #90780 in Analytic Geometry for marjel

Question #90780

find the standard equation of the circle C(3,-2) ; r=4

Expert's answer

In case the center of a circle C(a;b) and the radius r, the standard form of a circle equation is (x-a)^{2}+(y-b)^{2}=r^{2}.

We get the equation of the circle in the form (x-3)^{2}+(y+2)^{2}=4^{2 }or (x-3)^{2}+(y+2)^{2}=16.

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