# Answer to Question #1232 in Analytic Geometry for olonade emmanuel

Question #1232

a bucket is 20cm in diameter at the open end, 12cm in diameter at the bottom and 16cm deep. to what depth would the bucket fill a cylindricial tin 28cm in diameter

Expert's answer

We have to evaluate the volume of the bucket:

V = 1/3 π H (R

The volume of the cylindricial tin is

V = π R

h = 5.33 cm

V = 1/3 π H (R

^{2}+ Rr +r^{2}) = 1/3 π *16 (20^{2}+20*12 +12^{2}) = 13136,0461 cm^{2}The volume of the cylindricial tin is

V = π R

^{2}h = π* 28^{2}*h = 13136,0461;h = 5.33 cm

**Answer:**the depth is 5.33 cm.Need a fast expert's response?

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