Answer to Question #4925 in Algebra for jojo alex
Question #4925
the sum of 2 numbers is 16 the sum of their reciprocals is 1/3 find the number ?
Expert's answer
Solution
We have two unknown numbers and two conditions on these numbers.
Let's designate these numbers through x , y.
Let's make system of the equations.
Let's solve system of the equations.
=> 
Thus
or 
Answer: These numbers are 4 and 12.
We have two unknown numbers and two conditions on these numbers.
Let's designate these numbers through x , y.
Let's make system of the equations.
Let's solve system of the equations.
=> Thus
or Answer: These numbers are 4 and 12.
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Comments
a+b=16
1/a+1/b=1/3
ab=48
a*(16-a)=48
a2-16a+48=0
a2-12a-4a+48=0
a(a-12)-4(a-12)=0
a=4,12
the numbers are following
1st number = 4
2nd number = 12
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