# Answer to Question #4925 in Algebra for jojo alex

Question #4925

the sum of 2 numbers is 16 the sum of their reciprocals is 1/3 find the number ?

Expert's answer

Solution

We have two unknown numbers and two conditions on these numbers.

Let's designate these numbers through x , y.

Let's make system of the equations.

Let's solve system of the equations.

=>

Thus

or

Answer: These numbers are 4 and 12.

We have two unknown numbers and two conditions on these numbers.

Let's designate these numbers through x , y.

Let's make system of the equations.

Let's solve system of the equations.

=>

Thus

or

Answer: These numbers are 4 and 12.

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## Comments

jayashree01.11.11, 13:12a+b=16

1/a+1/b=1/3

ab=48

a*(16-a)=48

a2-16a+48=0

a2-12a-4a+48=0

a(a-12)-4(a-12)=0

a=4,12

ihsan31.10.11, 23:34the numbers are following

1st number = 4

2nd number = 12

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