let's find roots of the following equation x^2+8xb+12b^2=0 Descriminant D=(64-48)b^2=(4b)^2 Hence x1=(-8b+4b)/2=-2b x2=(-8b-4b)/2=-6b So we have x^2+8xb+12b^2=(x+2b)(x+6b)
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