# Answer to Question #4706 in Algebra for Kevin

Question #4706

factor the following trinomial x^2+8xb+12b^2

Expert's answer

let's find roots of the following equation

x^2+8xb+12b^2=0

Descriminant D=(64-48)b^2=(4b)^2

Hence x1=(-8b+4b)/2=-2b

x2=(-8b-4b)/2=-6b

So we have x^2+8xb+12b^2=(x+2b)(x+6b)

x^2+8xb+12b^2=0

Descriminant D=(64-48)b^2=(4b)^2

Hence x1=(-8b+4b)/2=-2b

x2=(-8b-4b)/2=-6b

So we have x^2+8xb+12b^2=(x+2b)(x+6b)

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