# Answer to Question #34245 in Algebra for brady

Question #34245

36x^2+30x-36 is the product of 6x-4, and another. What is the other factor?

Expert's answer

36x^2+30x-36=6(6x^2+5x-6)

6x^2+5x-6=0

D=25+144=169

roots are x1,2=(-5+-13)/12

x1=-18/12=-3/2

x2=8/12=2/3

So, 36x^2+30x-36=6(6x^2+5x-6)=6*6(x+3/2)(x-2/3)=6(2x+3)(3x-2)=3(2x+3)(6x-4)=(6x+9)(6x-4)

6x^2+5x-6=0

D=25+144=169

roots are x1,2=(-5+-13)/12

x1=-18/12=-3/2

x2=8/12=2/3

So, 36x^2+30x-36=6(6x^2+5x-6)=6*6(x+3/2)(x-2/3)=6(2x+3)(3x-2)=3(2x+3)(6x-4)=(6x+9)(6x-4)

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