ONE TANK CAN BE FILLED UP BY TWO TAPS IN 6 HOURS. THE SMALLER TAP ALONE TAKES 5 HRS MORE THAN THE BIGGER TAP ALONE. FIND THE TIME REQUIRED BY EACH TAP TO FILL THE TANK SEPARATELY
1
Expert's answer
2013-03-01T04:43:10-0500
Suppose, the smaller tap alone fill tank in X hours and the bigger - in Y hours: X-Y=5 If they work together we need to add speeds of filling: V/X + V/Y = V/6, V - volume of tank Finally, we have a system of equations: X-Y=5 1/X+1/Y=1/6 And X>0 and Y>0 ( because it's time) From the first: X=Y+5 From the second: 1/(Y+5)+1/Y=1/6 *6*Y*(Y+5) 6Y+6*(Y+5)=Y(Y+5) Y^2+5Y-12Y-30=0 Y^2-7Y-30=0 Y1 = -3 Y2=10 X = 10+5 = 15 Answer: 10 and 15 hours.
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
APPROVED BY CLIENTS
"assignmentexpert.com" is professional group of people in Math subjects! They did assignments in very high level of mathematical modelling in the best quality. Thanks a lot
Comments
Leave a comment