Answer to Question #24103 in Algebra for Mike
x^4 - 6x^2 y^2 + 9y^4
x^4 - 6x²y² + 9y^4 = (x² - 3y²)2
And now let's use the difference of two squares formula:
(x² - 3y²) = (x - √3y)(x + √3y).
Now factorization is complete. Therefore,
x^4 - 6x^2 y^2 + 9y^4 = (x - √3y)2(x + √3y)2
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