# Answer to Question #16513 in Algebra for fazeela popow

Question #16513

factorize 3p^2-2p-5

Expert's answer

we find roots of the equation

3p^2-2p-5=0

D=4+4*3*5=4*16=64

p1,2=(2+-8)/6 so p1=-1, p2=5/3

so

3p^2-2p-5=3(p+1)(p-5/3)

3p^2-2p-5=0

D=4+4*3*5=4*16=64

p1,2=(2+-8)/6 so p1=-1, p2=5/3

so

3p^2-2p-5=3(p+1)(p-5/3)

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