# Answer to Question #13392 in Algebra for haidy

Question #13392

how can i do these problems 8x+6-9x=2-x-15 ,AND 3m-10=2(4M-5),AND 5-(n-4)=3(n+2),and 8(x+1)=4x-8

Expert's answer

Let's consider the first one (all the rest of your tasks are solved similarly):

8x+6-9x=2-x-15

Let's gather terms with x in the left part and the rest in the right

8x+6-9x & =& 2-x-15

& -6 & +x +x -6

hence we obtain:

8x-9x+x=2-15-6

0=-19

The equality we've obtained is false so this problem has no solution.

Another one

3m-10=2(4M-5)

3m-10=8m-10

5m=0 whence m=0

5-(n-4)=3(n+2)

5-n+4=3n+6

3=4n

whence n=3/4

8x+6-9x=2-x-15

Let's gather terms with x in the left part and the rest in the right

8x+6-9x & =& 2-x-15

& -6 & +x +x -6

hence we obtain:

8x-9x+x=2-15-6

0=-19

The equality we've obtained is false so this problem has no solution.

Another one

3m-10=2(4M-5)

3m-10=8m-10

5m=0 whence m=0

5-(n-4)=3(n+2)

5-n+4=3n+6

3=4n

whence n=3/4

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