Answer to Question #10018 in Algebra for Sonny
So, speed of
second vehicle v'=s/(8 sec)=25 mph
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v=25, t=8/3600=1/450 => s=vt=25/450=1/9
So, speed of the&
second vehicle v'=s/(3 sec)=1/27 mps=1/27*3600 mph=133.3 mph
I made a mistake in my problem. I am very sorry and appreciate your help. I need to know the speed of the second vehicle. It travels the distance in 3 sec. instead of the time I gave you for car #1.