Question #2945

At the end of the second day of the carnival some water was drained from the tank. the volume of water drained was 35.3 cubic feet. using your answer frm b detemine the height in feet of the water remaing in the tank after the water was drained. radius= 3 feet hieght is 5 feet but filled with 4 feet water answer from b is 75.3 cubic feet.

Expert's answer

Solution 1:

If V(from b)=75.3 cubic feet,

b=V_{b}/(πr^{2}) = 75.3/(3.14*3^{3})= 75.3/27.9=2.7 feet

Solution 2:

V(after drained) = V(tank) - V(drained) = πr^{2}*h-35.3 = 3.14*3^{2}*4-35.3=76.3 cubic feet

b=(V(after drained)) / (πr^{2}) = 76.3/ 27.9 = 2.7 feet

If V(from b)=75.3 cubic feet,

b=V

Solution 2:

V(after drained) = V(tank) - V(drained) = πr

b=(V(after drained)) / (πr

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