Answer to Question #17656 in Abstract Algebra for Tsit Lam

Question #17656
Using the definition of rad R as the intersection of the maximal left ideals, show directly that rad R is an ideal.
1
Expert's answer
2012-11-19T07:44:12-0500
For y ∈ rad R, r ∈ R, and many maximal left ideal, we must show that yr ∈ m. Assume otherwise; then Rr + m = R. Consider the left R-modulehomomorphism ϕ: R → R/m definedby ϕ(x) = xr (mod m).Since Rr + m = R, ϕis onto. This implies thatker(ϕ) is a maximal left ideal.Therefore, y ∈ ker(ϕ), so we have 0 = ϕ(y) = yr (mod m), acontradiction.

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