find the period of this equation
y=5sin((x/9)+(pi/6))
1
Expert's answer
2012-10-25T09:19:13-0400
let T be required period then y(x)=y(x+T) where T>0 is the smallest possible 5sin( x/9+ pi/9)=5sin((x+T)/9+pi/9) sin( x/9+ pi/9)=sin((x/9)+pi/9+T/9) so T/9=2pi ( using sin properties) then T=18*pi
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