Solution.
p2 = 1 bar;
p1 = 5 bar;
T3 = 283 K;
T1 = 298K;
pv1.3=constant;
L/d = 1.5;
cp = 1.005 kJ/kgK;
cv = 0.71 kJ/kgK;
;
Swept volume per stroke =13.36/(2 300) =0.02m3;
V = 0.02 0.85 = 0.019 m3;
Answer: theoretical C.O.P =1.92;
actual C.O.P = 0.96;
d=0.016m;
l = 0.024 m.
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