Answer to Question #208384 in Mechanical Engineering for aman

Question #208384

the capacity of a refrigeration is 200tr when working between -6°C and 25°C also find the power requirement to drive the unit


1
Expert's answer
2021-06-21T05:47:35-0400

Power input = "\\frac{RC * (T_H-T_L)}{T_L}"

But RC = 200TR x 335 KJ/kg = 703.371 kW

"P_{in}=\\frac{703.371*(25--6)}{267}"

"P_{in}=81.664 kW"


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