Answer to Question #187441 in Mechanical Engineering for randz

Question #187441

5. Ten kilograms of steam at 1.1 MPa has an internal energy of 31,228 kJ. Determine a) its

temperature , b) Total enthalpy.


1
Expert's answer
2021-05-05T07:40:41-0400

Specific internal energy of wet steam

u = h – pv

Specific volume of wet steam

v = x.v

Specific enthalpy of wet steam, h = h+ xhfg

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