Question #153653

The two cylindrical rod segments are fixed to the rigid walls such that there is a gap of 0.01in between

them when T1 = 60^{o}F. Determine the larger temperature T2 required in order to just close the gap

without producing stresses in the rods? Each rod has a diameter of 1.25in. Take (alpha)al = 13 x 10^{-6} in/in ^{o}F,

Eal = 104 ksi, (Alpha)cu = 9.4 x 10^{-6} in/in ^{o}F, Ecu = 15 x 10^{3} ksi.

Expert's answer

a)="\\Delta Cu + \\Delta Al = 0.01"

"L cu D cu (T2-T1) + L al D al (T2-T1) = 0.01"

"T2 = 112.4 F"

b)= "[-(12\\times9.4\\times10" ^{-6}) "- (6\\times13\\times10" ^{-6})]+"\\alpha [ \\frac{12} {10^4}+ \\frac{6}{1.500^4}]" = 0.01

= 34.87Ksi

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