Answer to Question #117564 in Material Science Engineering for robin

Question #117564
Calculate the amount of heat transfer required to change 88 kg of ice (solid state) which is at 00C to
water (liquid state) of 100C. The specific heat capacity of ice is 2090 J/kg0C and the specific latent heat
of fusion is 335 kJ/kg.
1
Expert's answer
2020-05-24T16:33:06-0400

q1 = m x ∆Hfus = 88 kg x 335 kJ/kg = 29 480 kJ

q2 = m x c x ∆T = 88 x 2090 J/kg•°C x (10 - 0)°C = 1 839 kJ

Q = q1 + q2 = 29 480 + 1 839 = 31 319 kJ


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be first!

Leave a comment

Ask Your question

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS