Calculate the amount of heat transfer required to change 88 kg of ice (solid state) which is at 00C to
water (liquid state) of 100C. The specific heat capacity of ice is 2090 J/kg0C and the specific latent heat
of fusion is 335 kJ/kg.
1
Expert's answer
2020-05-24T16:33:06-0400
q1 = m x ∆Hfus = 88 kg x 335 kJ/kg = 29 480 kJ
q2 = m x c x ∆T = 88 x 2090 J/kg•°C x (10 - 0)°C = 1 839 kJ
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
APPROVED BY CLIENTS
Finding a professional expert in "partial differential equations" in the advanced level is difficult.
You can find this expert in "Assignmentexpert.com" with confidence.
Exceptional experts! I appreciate your help. God bless you!
Comments
Leave a comment