Question #206770

Insulator capacitance of MOSFET 10 micro F . width of depletion layer 0.2 cm and permitivity is 33 . calculate total capacitance

Expert's answer

"C_{dep}=\\frac{\\epsilon}{w_{dep}}\\newline\n\n\\epsilon=33 \\newline\n\nw_{dep}=0.2cm=0.002m \\newline\n\nC_{in}=10\\mu F \\newline\n\nC_{dep}=\\frac{33} {0.002}=16500F=0.0165\\mu F \\newline"

Total capacitance is

"(C)=\\frac{C_{dep} \\times C_{in}}{C_{dep} + C_{in}} \\newline\n\nC=\\frac {0.0165 \\times 10}{0.0165+10} \\newline\n\nC=\\frac {0.165}{10.0165} \\newline\n\nC= 0.0165\\mu F=16.5nF"

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