Answer to Question #226508 in Civil and Environmental Engineering for syra

Question #226508
A 160 cm tall person lies on a light ( massless) board which is supported by two weighing scales, one under the feet and one beneath the top of the head. The two scales read, respectively, 29.4 and 32.8 kg. Where is the center of gravity of this person?
1
Expert's answer
2021-08-20T01:36:40-0400

The person would feel

Pushing up At the head

"F=mg\\\\F=32.8\\times9.8=321.4N"

The person would feel pushing up at the feet

"F=mg=29.4\\times9.8=288.1N"

The force of m

g would be an arrow pointing down under the center of gravity located from the bottom of the feet.for person to be in equilibrium "F_{net}" must = 0

so

"321.4+288.1=F\\\\F=609.6N"

Torque must also equal 0;


"321.44\\times1.6=609.56(x)\\\\x=0.844m\\\\x=84.4cm"

84.4 cm from the bottom of the feet .


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