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# Answer to Question #258257 in Chemical Engineering for MZ SEKHWELA

Question #258257
A mixture containing 10%ethanol and 90% water by weight is fed into a distillation column at the rate of 114.1kg/h.The distillate contains 76.4%ethanol and the distillate is produced at the rate of one tenth of that of the feed.perfom material balance and calculate the percentage of ethanol in the bottom.
1
2021-10-29T02:32:55-0400

mass of mixture = 106.26kg/hr

10% of the mixture is ethanol = 10.626 kg

number of moles of ethanol = "\\dfrac{10626\\text{g} }{46\\text{g\/mol}}"

= 231 moles

90% of the mixture is water = 95.634 kg

number of moles of water = "\\dfrac{95634\\text{g}}{18\\text{g\/mol}}"

= 5313 moles

Total number of moles = 231 + 5313 = 5544 moles

mole fraction of ethanol = 231/5544 = 0.0417

mole fraction of water = 5313/5544 = 0.9583

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