Question #234274

b) A homogenous liquid phase reaction with the given stoichiometry and kinetics A→S,-rA=kCA^2, takes place with 50% conversion in a mixed flow reactor. Find the conversion if this reactor is replaced by another mixed flow reactor having volume 6 times that of the original reactor-all else remain unchanged. Find the conversion if the original reactor is replaced by a plug flow of the same size- all else remains unchanged.

Expert's answer

According to the rate of the reaction, the reaction is of second order. The conversion in a mixed flow reactor is, "X_a=0.5" ForFor a mixed flow reactor, the general reactor design equation is "\\frac{V}{F_{A0}}=\\frac{X_a}{r_a}"

where *V* is the volume of the reactor, "F_{A0}" is volumetric flow rate, "C_{A0}" is the initial concentration of A, and −r is the rate of the equation. In Plug flow reactor,"\\frac{V}{F_{A0}}=\\frac{dX_a}{r_a}" where all the terms have similar notations to mixed flow reactor.

a) The volume of the new reactor is 6 times the volume of the original reactor, V'=6*×*V

"V'=6\u00d7V"

Therefore,

The conversion can never be greater than 1. So, the conversion is **0.75.**

**b) **In the case of PFR,"\\frac{V}{F_{A0}}=\\frac{dX_a}{r_a}"

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