Answer to Question #223923 in Chemical Engineering for Lokika

Question #223923

A composite wall is formed of a 2.5 cm copper plate (k=385 W/m-K). a 3.2 cm layer of


asbestos (k=0.2 W/m-K), and a 5 cm layer of fibreglass (k=0.045 W/m-K). The wall is subjected to an overall temperature drop of 560°C. Calculate the heat flux through the composite wall and also determine the temperature drop across the asbestos layer?


1
Expert's answer
2021-09-10T00:03:51-0400

Thickness of copper plate = 2.5cm

kc = 385 W/m.K

thickness of absestos = 3.2cm

ka = 0.2 W/m.K

thickness of fireglass = 5cm

kf = 0.045 W/m.K

∆T = 560°

rate of heat loss (Q) =


RthC = "\\dfrac{L_c}{k_cA} = \\dfrac{2.5\u00d710^{-2}}{385\u00d71}"


"= 6.5\u00d7 10^{-5}\u00b0C\/W"


RthA = "\\dfrac{L_A}{k_AA} = \\dfrac{3.2\u00d710^{-2}}{0.2\u00d71}"


"=0.16\u00b0C\/W"


RthF = "\\dfrac{L_F}{k_FA} = \\dfrac{5\u00d710^{-2}}{0.045\u00d71}=1.11\u00b0C\/W"


"Q = \\dfrac{\u2206T}{R_{thC}+R_{thA}+R_{thF}}="


"\\dfrac{560}{6.5\u00d710^{-5}+0.16+1.11}= 440.92\\ W"

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