Question #159380
A pipe connecting 2tanks contains 4 standard elbows, a plug valve that is half opened.The line is a commercial steel pipe, 25mm internal diameter,the length of the pipe is 120m, the properties of fluid are viscosity=0.99N/m^2s, fluid density 998kg/m^3, calculate the pressure draw due to friction when the fluid rate is 3500kg/hr
1
2021-02-01T09:28:11-0500

Velocity of flow V = Q/A = (3500 kg / (3600 s x 998 kg/m3)) / (/4 x (0.025 m)2) = 1.986 m/s

Reynolds number, Re = VD/ = (998 kg/m3 x 1.986 m/s x 0.025 m) / 0.099Ns/m2 = 500

The Reynolds number is less than 2000. So the flow is laminar.

For laminar flow, Friction factor f = 64/Re = 64/500 = 0.128

Head loss, HL = f(L/D)(V2/2g) = 0.128 x (120 m / 0.025 m) x ((1.986 m/s)2 / 2 x 9.81 m/s2) = 121.4 m

Pressure drop = HL = 998 kg/m3 x 9.81 m/s2 x 121.4 m = 11.9 x 105 Ns/m2 = 12 bar

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