Answer to Question #201435 in Physical Chemistry for madison

Question #201435

Does a precipitate form if you add 15.00 π‘šπΏ of a 2.10 Γ— 10βˆ’3 π‘šπ‘œπ‘™/𝐿 solution of lead (II) nitrate to 25.00 π‘šπΏ of a 2.50 Γ— 10βˆ’2 π‘šπ‘œπ‘™/𝐿 solution of potassium chloride? Justify your answer mathematically. (𝐾𝑠𝑝 π‘“π‘œπ‘Ÿ π‘™π‘’π‘Žπ‘‘(𝐼𝐼)𝑐hπ‘™π‘œπ‘Ÿπ‘–π‘‘π‘’ 𝑖𝑠 1.7 Γ— 10βˆ’5)


1
Expert's answer
2021-06-01T02:52:21-0400

Lead nitrate and potassium chloride reaction:


Pb(NO3)2(aq) + 2KCl(aq) + PbCl2(8) 1 + 2KNO3(aq)


Concentration of lead nitrate:


Molarity = 2.50 Γ— 10βˆ’3 mol/L


Volume = 25.00 mL


1000 mL solution of lead nitrate has 2.50 Γ— 10βˆ’3 moles


So, 25.00 mL solution of lead nitrate has (2.50 Γ— 10βˆ’3 / 1000) x 25 = 62.5 x 10-6 = 6.25 x 10-5 moles.


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