What characterizes in general a basic solution is the presence of hydroxide ions, when adding a base to the water, the base B takes from the water molecule a proton H+, thus obtaining BH+ and OH-
B + H2O → BH+ +OH-
The same thing occurs with NH3: NH3 + H2O → NH4+ +OH-
but with NaOH it's different, we don't represent the water molecule in the equation, we just write:
NaOH → Na+ +OH-
What is the role of the water in this case, I know there's a phenomen of dilution, but there must be a proton exchange?
Thank you
1
Expert's answer
2012-09-13T12:07:45-0400
Actually we can write the same with NaOH NaOH+ H2O <=> NaOH2+ OH- (analogy with water 2H2O <=>H30+ + OH-) but it makes no sense . NH3 must get form NH4+ to be written in some compound, and Na must get Na+ Its just formalism and the reason of this is 1 atom of H, which is need to make some equation
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
APPROVED BY CLIENTS
Finding a professional expert in "partial differential equations" in the advanced level is difficult.
You can find this expert in "Assignmentexpert.com" with confidence.
Exceptional experts! I appreciate your help. God bless you!
Comments
Leave a comment