61 751
Assignments Done
97,8%
Successfully Done
In May 2018

Answer to Question #1339 in Physical Chemistry for William

Question #1339
Calculate the Stoichiometric air/fuel ratio for the complete combustion of Octane (CH8H18)

Expert's answer
2CH8H18 + 15O2 = 2CO2 + 26H2O

a molecular weight of Octane is 12 + 26 = 38
a molecular weight of oxygen molecula is 16*2 = 32
Thus the oxygen-fuel mass ratio is OFR = 15*32/2*38 = 6.316
There is 23.2 mass-percent of oxygen in the air, then
AFR = M(air)/M(fuel) = OFR / 0.232 = 6.316/0.232 = 27.22

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be first!

Leave a comment

Ask Your question

Submit
Privacy policy Terms and Conditions