# Answer to Question #11464 in Physical Chemistry for Damini

Question #11464

5.6L of gas at STP weighs equal to 8g.The vapor density of the gas is

Expert's answer

STP = "standard temperature and pressure" as a temperature of 273.15 K (0 °C, 32

°F) and an absolute pressure of 100 kPa (14.504 psi, 0.986 atm, 1 bar). R =

8.314 L*kPa / K*mol

pV = nRT = mRT/M

Vapour density is the density of a

vapour in relation to that of hydrogen. Therefore:

vapour density = molar

mass of gas / molar mass of H2 = molar mass of gas / 2.0016

Molar mass is

M = mRT / pV = 8g * 8.314L*kPa/K*mol * 273.15K / 100kPa * 5.6L = 32

g/mol

vapour density = 32g/mol / 2g/mol = 16

The vapor density of the gas

is 16.

°F) and an absolute pressure of 100 kPa (14.504 psi, 0.986 atm, 1 bar). R =

8.314 L*kPa / K*mol

pV = nRT = mRT/M

Vapour density is the density of a

vapour in relation to that of hydrogen. Therefore:

vapour density = molar

mass of gas / molar mass of H2 = molar mass of gas / 2.0016

Molar mass is

M = mRT / pV = 8g * 8.314L*kPa/K*mol * 273.15K / 100kPa * 5.6L = 32

g/mol

vapour density = 32g/mol / 2g/mol = 16

The vapor density of the gas

is 16.

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