Answer to Question #73528 in Chemistry for Katelyn

Question #73528
What mass of ammonium nitrate is required to lower the temperature of 400 mL of
water from 25 oC to 1oC? The Hsoln for ammonium nitrate is 34 kJ/mol.
1
Expert's answer
2018-02-15T07:15:45-0500
400 ml = 400 g of water
ΔT = 25 – 1 = 24 o
C
C = 4.18 J/g∙C
Q = cmΔT = 4.18 J/g∙C x 400 g x 24 C = 40128 J = 40.128 kJ
40.128 kJ / 34 kJ/mol = 1.18 mol of ammonium nitrate required
80.043 g/mol x 1.18 mol = 94.45074 g.
Answer: 94.45074 g.

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Comments

Assignment Expert
15.02.18, 15:10

Dear Katelyn, it just influnces on the sign of Q, which means energy releasing or consumption. Since it is irrelevant in this problem, one can use any ΔT definition.

Katelyn
15.02.18, 14:40

Wouldn’t deltaT be 1-25= -24? Since deltaT is tfinal-tinitial?

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