under suitable conditions, thiourea is oxidized to sulfate by bromate:
3CS(NH2)2 + 4BrO3- + 3H2O --- 3CO(NH2)2 + 3SO4 + 4Br- + 6H+
a 0.0 715g sample of material was found to consume 14.1mL of 0.00833 M KBrO3. What was the % purity of the thiourea sample?
P.S this is analytical chem..... Thanks for the answer in advance