Question #33008

Ca3(PO4)2 + 4H3PO4 -- 3Ca (H2OP4)4

calculate the required mass of Ca3(PO4)2 to obtain

100g of Ca (H2OP4)4

calculate the required mass of Ca3(PO4)2 to obtain

100g of Ca (H2OP4)4

Expert's answer

Ca_{3}(PO_{4})_{2} + 4H_{3}PO_{4} -- 3Ca(H_{2}PO_{4})_{2}

m of Ca(H_{2}PO_{4})_{2} is 100g

First of all we can find the amount of substance of Ca(H_{2}PO_{4})_{2}. We can use the formula

n = m/M

where

n - the amount of substance

m - the mass

M - the molar mass, which is calculated: M(Ca(H_{2}PO_{4})_{2}) = 40 +4*2*1+4*16+31*4*4 = 31+ 3 *1 = 608 g/mol

n(Ca(H_{2}PO_{4})_{2}) = 100 g / 608 g/mol = 0.164 moles

According the equation Ca_{3}(PO4)_{2} + 4H_{3}PO_{4} --> 3Ca(H_{2}PO_{4})_{2} we can find the amount of substance of Ca_{3}(PO_{4})_{2}:

n(Ca_{3}(PO_{4})_{2}) = n(Ca(H_{2}PO_{4})_{2})/3 = 0.164/4 = 0.04 moles

M(Ca_{3}(PO_{4})_{2} = 310 g/mol

m(Ca_{3}(PO_{4})_{2}) = 0.04moles * 310 g/mol = 12.4g

Answer: 12.4g

m of Ca(H

First of all we can find the amount of substance of Ca(H

n = m/M

where

n - the amount of substance

m - the mass

M - the molar mass, which is calculated: M(Ca(H

n(Ca(H

According the equation Ca

n(Ca

M(Ca

m(Ca

Answer: 12.4g

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