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Answer to Question #24927 in Other Chemistry for Ritu

Question #24927
Sir i have to prepare solution of molar ratio for FeCl3/Pyrrole is 2.2 (Mol.wt of FeCl3 is 162.2 and Mol. wt of pyrrole is 67.09) in 30 ml distilled water and FeCl3 concentration is 14wt%. Please tell me how much pyrrole has taken and how to calculate it. Please reply me soon. Thanks
Expert's answer
If you will take 30 ml of aqua (water) solution of FeCl3 with concentration 14 wt%, the mass of& FeCl3 in this solution will be: 30•0.14=4.2 g. So that, the number moles of FeCl3 are: 4.2/162.2=0.026 moles. The number moles of Pyrrole are: 0.026/2.2=0.011 moles (if the ratio FeCl3: Pyrrole is 2.2:1), and mass Pyrrole which you should take: 0.011•67.09=0.79 g.

Answer: the mass pyrrole is 0.79 g.

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