Question #23984

How many hydrogen atoms are in 0.1731 mol of H2SO4?

Expert's answer

H_{2}SO_{4} includes two atoms of hydrogen,so we can write its like:

H_{2}SO_{4} -----> 2H^{+} + SO_{4}^{2-}

One mole of compound consist of 6.02 *10^23 molecules. It is Avogadro constant. Now we can calculate hydrogen atoms:

0.1731 mol N

H_{2}SO_{4} -----> 2H^{+} + SO_{4}^{2-}

1 2* 6.02 *10^23

N = (0.1731* 2* 6.02 *10^23 )/1 = 2.084 *10^23 atoms

H

One mole of compound consist of 6.02 *10^23 molecules. It is Avogadro constant. Now we can calculate hydrogen atoms:

0.1731 mol N

H

1 2* 6.02 *10^23

N = (0.1731* 2* 6.02 *10^23 )/1 = 2.084 *10^23 atoms

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