Question #205754

A sample of argon gas takes up 7 L and has a temperature of 250 K. After being heated to temperature 280K, what is the new volume? (Use V₁/T₁ = V₂/T₂ ... Show the appropriate formula and math work for credit.)

Expert's answer

V_{1 }= 7 L

T_{1} = 250 K

V_{2} = unknown

T_{2} = 280 K

P_{1} = P_{2} = const

**Solution:**

Since the pressure and amount of gas remain unchanged, Charles' Law can be used.

Charles' Law can be expressed as: V_{1} / T_{1} = V_{2} / T_{2}

V_{1}T_{2} = V_{2}T_{1}

To find the new volume, solve the equation for V_{2}:

V_{2} = V_{1}T_{2} / T_{1}

V_{2} = (7 L × 280 K) / (250 K) = 7.84 L

V_{2} = 7.84 L

**Answer: 7.84 L is the new volume.**

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