Question #205602

What volume of a 1.60 mol/L ** stock solution **of calcium chloride would you use to make a 530 mL of a 0.34 mol/L solution?

Expert's answer

C_{1} = 1.60 mol/L

V_{1} = unknown

C_{2} = 0.34 mol/L

V_{2} = 530 mL

**Solution:**

The equation for dilution calculations can be used.

where:

c_{1}, V_{1} - the molarity and volume of the concentrated solution (stock solution)

c_{2}, V_{2} - the molarity and volume of the diluted solution

Thus:

(1.60 mol/L) × V_{1} = (0.34 mol/L) × (530 mL)

V_{1} = (0.34 mol/L × 530 mL) / (1.60 mol/L) = 112.625 mL = 112.6 mL

**V**_{1}** = 112.6 mL**

**Answer: 112.6 mL**

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