What volume of a 1.60 mol/L stock solution of calcium chloride would you use to make a 530 mL of a 0.34 mol/L solution?
C1 = 1.60 mol/L
V1 = unknown
C2 = 0.34 mol/L
V2 = 530 mL
The equation for dilution calculations can be used.
c1, V1 - the molarity and volume of the concentrated solution (stock solution)
c2, V2 - the molarity and volume of the diluted solution
(1.60 mol/L) × V1 = (0.34 mol/L) × (530 mL)
V1 = (0.34 mol/L × 530 mL) / (1.60 mol/L) = 112.625 mL = 112.6 mL
V1 = 112.6 mL
Answer: 112.6 mL