Answer to Question #205602 in Chemistry for marianna

Question #205602

 What volume of a 1.60 mol/L stock solution of calcium chloride would you use to make a 530 mL of a 0.34 mol/L solution?


1
Expert's answer
2021-06-11T05:37:53-0400

C1 = 1.60 mol/L

V1 = unknown

C2 = 0.34 mol/L

V2 = 530 mL


Solution:

The equation for dilution calculations can be used.



where:

c1, V1 - the molarity and volume of the concentrated solution (stock solution)

c2, V2 - the molarity and volume of the diluted solution


Thus:

(1.60 mol/L) × V1 = (0.34 mol/L) × (530 mL)

V1 = (0.34 mol/L × 530 mL) / (1.60 mol/L) = 112.625 mL = 112.6 mL

V1 = 112.6 mL


Answer: 112.6 mL

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