Answer to Question #200208 in Chemistry for Hersona G

Question #200208

How many grams are contained in 3.5 moles of N2O7


1
Expert's answer
2021-05-31T02:01:56-0400

Solution:

N2O7 - nitroperoxynitrate

The molar mass of N2O7 is 140.01 g/mol.

Therefore,

(3.5 mol N2O7) × (140.01 g N2O7 / 1 mol N2O7) = 490.035 g N2O7 = 490 g N2O7


Answer: 490 grams are contained in 3.5 moles of N2O7.

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