Answer to Question #19834 in Other Chemistry for Cierra
how grams of CO22 would be formed when 76.2g of acetylene (C2H2(g)) burns completely?
The reaction of acetylene burning:
2C2H2 + 5O2 = 4CO2 + 2H2O
The acetylene molar mass is 2*12+2*1=26 g/mol The amount of acetylene is n(C2H2) = m(C2H2)/M(C2H2) = 76.2 g / 26 g/mol = 2.93mol According to reaction above, the amount of CO2 is n(CO2) = 2*n(C2H2) = 2.93*2 = 5.86 mol The mass of CO2 is m(CO2) = n(CO2)*M(CO2) = 5.86 mol * 44 g/mol = 257.8 g