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Answer to Question #19834 in Other Chemistry for Cierra

Question #19834
how grams of CO22 would be formed when 76.2g of acetylene (C2H2(g)) burns completely?
Expert's answer
The reaction of acetylene burning:

2C2H2 + 5O2 = 4CO2 + 2H2O

The acetylene molar mass is 2*12+2*1=26 g/mol The amount of acetylene is
n(C2H2) = m(C2H2)/M(C2H2) = 76.2 g / 26 g/mol = 2.93mol According to reaction above, the amount of CO2 is
n(CO2) = 2*n(C2H2) = 2.93*2 = 5.86 mol
The mass of CO2 is
m(CO2) = n(CO2)*M(CO2) = 5.86 mol * 44 g/mol = 257.8 g

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