Answer to Question #194498 in Chemistry for Jamel

Question #194498

A 0.674\,\text M


0.674M

0, point, 674, start text, M, end text

 cobalt(II) chloride (\text{CoCl}_2


CoCl2

start text, C, o, C, l, end text, start subscript, 2, end subscript

) solution is prepared with a total volume of 0.0750\,\text{L}


0.0750L

0, point, 0750, start text, L, end text

. The molecular weight of \text{CoCl}_2


CoCl2

start text, C, o, C, l, end text, start subscript, 2, end subscript

 is 128.9\,\dfrac{\text{g}}{\text{mol}}


128.9mol


g

128, point, 9, start fraction, start text, g, end text, divided by, start text, m, o, l, end text, end fraction

.

What mass of \text{CoCl}_2

CoCl2

start text, C, o, C, l, end text, start subscript, 2, end subscript

 (in grams) is needed for the solution?

Express the answer using 3 significant figures.

1
Expert's answer
2021-05-18T07:52:38-0400

A 0.674 M cobalt(II) chloride (CoCl2) solution is prepared with a total volume of 0.0750 L. The molecular weight of CoCl2 is 128.9 g/mol. What mass of CoCl2 (in grams) is needed for the solution?

Express the answer using 3 significant figures.


Solution:

Molarity of CoCl2 solution = Moles of CoCl2 / Solution volume

Moles of CoCl2 = Mass of CoCl2 / Molecular weight of CoCl2

Molarity of CoCl2 solution = Mass of CoCl2 / (Molecular weight of CoCl2 × Solution volume)

Therefore,

Mass of CoCl2 = Molarity of CoCl2 solution × Molecular weight of CoCl2 × Solution volume

Mass of CoCl2 = (0.674 mol L-1) × (128.9 g mol-1) × (0.0750 L) = 6.5159 g = 6.52 g

Mass of CoCl2 = 6.52 g


Answer: 6.52 grams of CoCl2 is needed for the solution.

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