76 331
Assignments Done
Successfully Done
In May 2019

Answer to Question #17791 in Other Chemistry for Tyler

Question #17791
How many moles are in 202 g of calcium carbonate (CaCO3)?
Answer in units of mol
Expert's answer
m(CaCO3) = 202 g;
n(CaCO3) = 202 / 100 = 2.02 mol

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!


No comments. Be first!

Leave a comment

Ask Your question

Privacy policy Terms and Conditions