Answer to Question #15266 in Other Chemistry for JoNae
Observe the following RXN:
CH4 + O2 --> CO + 2H2O
Carbon has a mass of 12 amu, Hydrogen 1 amu and Oxygen 16 amu.
If 16g of CH4 and 32g of O2 are reacted, how much CO is produced?
The amount of CH4 is n(CH4) = m(CH4)/M(CH4) = 16/16 = 1 mol The amount of O2 is n(O2) = M(O2)/M(O2) = 32/32 = 1 mol According to the reaction the amount of CO is equal to the amount of CH4 and O2. Thus the amount of CO is n(CO) = n(O2) = n(CH4) = 1 mol The mass of CO is m(CO) = n(CO)*M(CO) = 1*28 = 28 g