Calculate the volume of sebacoyl chloride required to prepare a 0.19 M solution of sebacoyl chloride in 21.6 ml cyclohexane. The molecular weight of sebacoyl chloride is 239.14 g/mol and the density is 1.12 g/ml ?
If C – concentration of the solution (M), V – volume of the solution (ml), x – chemical amount of sebacoyl chloride (mmole) then:
C = x/V; C = 0,19 M; V = V (cyclohexane) + V(sebacoyl chloride)*= 21,6 + 239,14*x/1,12*1000; 0,19 = x/ (21,6 + 239,14*x/1,12*1000); x = 4,28 mmole; V (sebacoyl chloride) = 239,14*4,28/1,12*1000 = 0,91 (ml). *We consider that the volume of final solution is equal to the sum of two mixing liquids (what in general case is not true).