Answer to Question #65657 in Organic Chemistry for Jamikeca Norris

Question #65657
The half-life of the radioisotope carbon-14 is 5730 years. How much C-14 will be left after 3 half-lives, if the initial amount is 100.0 g?
1
Expert's answer
2017-03-01T08:53:49-0500
Solution:
We find the part remaining after 3 half-lives:
(1/2)3 = 0.125
We find how much is left:
100.0 g x 0.125 = 12.5 g remain

Answer: 12.5 g C-14 will be left after 3 half-lives

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