Answer to Question #24208 in Organic Chemistry for tanmay khare
2HC=CH + 3O2 = 4CO2 + 2H2O
Volume is next:
V= 50 * 3 /2 = 75 cm3 of Oxygen required for this burning.
If 75 cm3 is 20 %
x is 100%
x= 375 cm^3 of air.
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