Question #21612

Sulphuric acid reacts with potassium to form potassium sulphate and hydrogen. Determine the mass of potassium sulphate produced if 6.0g of hydrogen wa also formed

Expert's answer

2K + H_{2}SO_{4} = K_{2}SO_{4} + H_{2}

if m(H_{2}) = 6 g, so

n(H_{2}) = 6 g / 2 g/mol = 3 moles;

n(H_{2}) : n(K_{2}SO_{4}) = 1 : 1;

n(K_{2}SO_{4}) = 3 moles;

m(K_{2}SO_{4}) = n(K_{2}SO_{4}) * M(K_{2}SO_{4})

M(K_{2}SO_{4}) = 39*2 + 32 + 64 = 174 g/mol;

m(K_{2}SO_{4}) = 3 moles * 174 g/mol = 522g

if m(H

n(H

n(H

n(K

m(K

M(K

m(K

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