Answer to Question #101345 in Organic Chemistry for MS

Question #101345
If you reacted 112 mg of maleic anhydride and 0.11mL of (E,E)-2,4-hexadien-1-ol what is your theoretical yield and what is the limiting reagent. I understand how to find the limiting reagent. The calculations are shown below. I need help with the theoretical yield please!!! The limiting reagent is (E,E)-2,4-hexadien-1-ol. Maleic anhydride: 112 mg x (10-3g/ 1 mg) = 0.112 g 0.112 g x (1 mol/98.06g)= 0.00114 mol (E,E)- 2,4-hexadien-1-ol : 0.11 mL x (0.871g/ 1mL) =0.09581 g 0.09581 g x (1 mol/ 98.14g) = 0.000976 mol [limiting reagent]
1
Expert's answer
2020-01-16T04:09:34-0500

Answer: Theoretical yield = mol of product/ moles of reactant.

This is an diene and dienophile reaction to form single product through cyclization reaction.

As the percentage conversation is not mention, so reaction will progress as long as limiting reagent is there.

Here the value of mole of reactant is decided by the limiting reagent.


This is an addition reaction of two components.

So, mol of product = mol of limiting reagent.

So, Theoretical yield is 100%.




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