Question #9750

A balloon is inflated to a volume of 1.250 L with dry hydrogen gas, at 28.0 °C. The balloon is then
cooled, and its volume drops to 964 mL. If the pressure is unchanged, what is the hydrogen gas temperature (in °C) in the cooled balloon? Assume that no gas has been added or removed.

Expert's answer

PV=nRT

n=const

(P1V1)/T1=(P2V2)/T2

P=const

V1/T1=V2/T2

1.250/(273+28)=0.964/x

x=232.3

K= -40.7 C

n=const

(P1V1)/T1=(P2V2)/T2

P=const

V1/T1=V2/T2

1.250/(273+28)=0.964/x

x=232.3

K= -40.7 C

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