Question #9750

A balloon is inflated to a volume of 1.250 L with dry hydrogen gas, at 28.0 °C. The balloon is then

cooled, and its volume drops to 964 mL. If the pressure is unchanged, what is the hydrogen gas temperature (in °C) in the cooled balloon? Assume that no gas has been added or removed.

cooled, and its volume drops to 964 mL. If the pressure is unchanged, what is the hydrogen gas temperature (in °C) in the cooled balloon? Assume that no gas has been added or removed.

Expert's answer

PV=nRT

n=const

(P1V1)/T1=(P2V2)/T2

P=const

V1/T1=V2/T2

1.250/(273+28)=0.964/x

x=232.3

K= -40.7 C

n=const

(P1V1)/T1=(P2V2)/T2

P=const

V1/T1=V2/T2

1.250/(273+28)=0.964/x

x=232.3

K= -40.7 C

## Comments

## Leave a comment