Answer to Question #93434 in Inorganic Chemistry for Saitama kalbo

Question #93434
A pure gold (24k) has a density of 19.32g/cm3. A wedding band weighs 3.50 grams. How much water must it displace (i.e what must its volume be?) if the band is in fact 24k gold?
1
Expert's answer
2019-08-28T04:48:17-0400

24k (k for karats) gold is a really pure one and it means that the band is made of a pure metal, which was quite strange for me. I never saw a band made of the pure gold. However, the volume, mass and density are all interrelated to each other as the following expression:

"V(gold)=\\frac{m(gold)}{d(gold)}"

Thus,

"V(gold)=\\frac{3.50g}{19.32g\/cm^3}=0.181cm^3"

We can also say that it is 0.181 mL or 1.81*10-4 L of possibly displaced water (when the band will be sank in water).

P.S. The jewelry gold metal is always a complicated alloy of gold, silver, nickel and copper.


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