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Answer to Question #9036 in Inorganic Chemistry for Jordan M Maxwell

Question #9036
Calculate the fluoride ion concentration and pH of a solution that is 0.20 M in
HF and 0.10 M in HCl
Expert's answer
HCl is strong acid and strong electolytet,his means that it breaks up into ions completely,so pH is -log[H+] = -log[HCl] = -log[0.1] = 1, but HF is weak acid and
it breaks up into ions not compleatly,and we need to use Ka which is 3.39 x
10^-4, so pH for HF is:

Ka = [H+][F-]/[HF] = [H+]^2/[HF]
[H+]^2 = Ka[HF] = 3.39 x 10^-4 * 0.1 = 3.39 x 10^-5
[F-] = [H+] = (3.39x 10^-5)^1/2 = 0.0058
pH = -log[H+] = 2.237

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