Calculate the fluoride ion concentration and pH of a solution that is 0.20 M in
HF and 0.10 M in HCl
1
Expert's answer
2012-05-08T12:00:51-0400
HCl is strong acid and strong electolytet,his means that it breaks up into ions completely,so pH is -log[H+] = -log[HCl] = -log[0.1] = 1, but HF is weak acid and it breaks up into ions not compleatly,and we need to use Ka which is 3.39 x 10^-4, so pH for HF is:
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